To what extent is the load capacity of an anchor influenced by a small edge distance, or by a small center-to-center distance between anchors? That question is asked regularly.
If we assume fixings in concrete, the center-to-center distance (Center distance) and edge distance can indeed play a role in the load capacity. A possible form of failure in case of overload is concrete cone fracture or concrete edge fracture. If two anchors, eg chemical anchors , are placed so close to each other that the theoretical concrete cones overlap, there is on balance less concrete to fail than in a situation where the cones do not overlap. And that obviously has a negative influence on the load capacity.
In order to determine to what extent the load capacity is reduced, it is important to distinguish between two concepts:
If the actual HOH distance or edge distance is greater than or equal to the given characteristic value (Scr and Ccr respectively), then the load capacity does not have to be reduced. However, if the actual HOH distance or edge distance becomes smaller than this characteristic value, the permissible load capacity must be reduced. Keep in mind that the actual HOH distance or edge distance may therefore never be lower than the minimum value (Cmin and Smin).
The reduction factor for a reduced HOH distance or edge distance can be calculated by summarizing the relevant reduction factors from the ETAG001 Annex C in one simple formula:
Reduction factor Rand Fc: 0.35 + (C/Scr) + 0.6 * (C 2 /S 2 cr)
Reduction factor heart to heart Fs: (1.0 + S/Scr) * 0.5
Whereby applies:
A calculation example
Let's assume a Sympafix STAM Sleeve Anchor M8x55mm in the pressure zone of concrete. The technical documentation states that this anchor can take up to 6.5 kN tensile force. It can also be found here that the characteristic HOH distance is 180mm and the characteristic edge distance is 90mm (the minimum values are respectively 90mm and 60mm). Suppose that in an anchoring situation there are two anchors with an HOH distance of 150mm.
The load capacity can then be calculated as follows:
(1.0 + S/Scr) * 0.5 = (1.0 + 150/180) * 0.5 = 0.92
For two anchors with a mutual distance of 150 mm, the load capacity is as follows:
2 * 6.5 * 0.92 = 11.9 kN
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